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Solve the equationx^3+\left(y^'\right)^3-3xy^'\:=0
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Solve the equation
x^3+\left(y^'\right)^3-3xy^'\:=0

User Florian Barth
by
4.3k points

1 Answer

6 votes

Answer:0

Explanation:

3x=3xy

x=0

y=0

3 times 0 = 0

User Trevor Eyre
by
4.1k points
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