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Write the equation of the directrix of the parabola shown below.

y^2+16y+4x+4=0

1 Answer

2 votes

Answer:

Hello,

F=(14,-8)

directrice: x=16

Explanation:

Making reduce form:


y^2+16y+4x+4=0\\y^2+2*8y+64-64+4x+4=0\\\\(y+8)^2-60+4x=0\\\\x=-((x+8)^2)/(4) +15\\

Since i prefere working with y=...: exchanging x and y


y=-((x+8)^2)/(4) +15\\\\Comparing\ to\ y=((x-a)^2)/(2(b-k)) +(b+k)/(2) \\\\a=-8 :\ S=(-8,15)\\\\\\b-k=-2\ and\ b+k=30 \ \longrightarrow\ b=14\ and\ k=16\\\\Exchanging\ x\ and\ y:\\\\Focus=(14,-8)\\\\x=16

Write the equation of the directrix of the parabola shown below. y^2+16y+4x+4=0-example-1
User Roman Scher
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