Question

1. A bicycle initially moving with a velocity

5.0 m s-1 accelerates for 5 s at a rate of 2 m s? Wh
will be its final velocity ?
​

Answer 1

`\boxed {\boxed {\sf 15 \ m/s \ or \ 15 \ m*s^(-1)}}`

Step-by-step explanation:

We are asked to find the final velocity. We are given the acceleration, time, and initial velocity, so we can use the following kinematics formula.

`v_f= v_i+ at`

In this formula,
`v_f` is the final velocity,
`v_i` is the initial velocity,
`a` is the acceleration, and
`t` is the time.

The bicycle has an initial velocity of 5.0 m *s⁻¹ or m/s, acceleration of 2 m/s², and a time of 5 seconds.

`\bullet \ v_i = 5.0 \ m/s \\\bullet \ a= 2\ m/s^2\\\bullet \ t= 5 \ s`

Substitute the values into the formula.

`v_f=5.0 \ m/s + ( 2\ m/s^2 * 5 \ s)`

Solve inside the parentheses.

• 
  `\frac {2 \ m}{s^2}* 5 \ s = ( 2 \ m)/(s) * 5 = ( 10 \ m)/(s) = 10 \ m/s`

`v_f= 5.0 \ m/s + (10 \ m/s)`

Add.

`v_f= 15 \ m/s`

The units can also be written as:

`v_f= 15 \ m*s^(-1)`

The bicycle's final velocity is 15 meters per second.