Answer:
y = 54/25 when x = 4.
Explanation:
y is given by the equation:

Where p and q are numbers.
We are also given that when x = 1, y = 10 and when x = 6, y = 0.7776.
And we want to determine the value of y when x = 4.
Since y = 10 when x = 1:

Simplify:

Any number (except for zero) to the zeroth power is one. Hence:

Thus, our equation is now:

When x = 6, y = 0.7776. Thus:

Simplify and divide both sides by ten:

Take the fifth root of both sides:
![\displaystyle q = \sqrt[5]{0.07776}](https://img.qammunity.org/2022/formulas/mathematics/college/4iwz8wcvdta4p16a38kz5df4kvd93sgfet.png)
Use a calculator. Hence:

Our completed equation is:

Then when x = 4, y equals:
