Answer:
y = 54/25
Explanation:
y = p×q^(x-1)
when x = 1 then y = 10
so,
10 = p×q^(1-1)
or, 10 = p×1
or, p = 10
when x = 6 then y = 0.7776
0.7776=p×q^(6-1)
or, 0.7776=p×q^5
or, 0.7776=10×q⁵
[0.7776 = 7776/10000 = 486/625]
or, 486/625 = 10×q⁵
or, 486/6250=q⁵
or,
![\frac{ \sqrt[5]{486} }{ \sqrt[5]{6250} } = q](https://img.qammunity.org/2022/formulas/mathematics/college/60n4fs3htro03k3aba1hjsvot7kovvrbme.png)
or,
![q = \frac{3 \sqrt[5]{2} }{5 \sqrt[5]{2} }](https://img.qammunity.org/2022/formulas/mathematics/college/2hbhu5vdrqx86bg1pt4kfiq5jn06mil1xt.png)
or, q = 3/5
so, when x = 4
y = p×q^(x-1)
y = 10×(3/5)^(4-1)
y = 10×(3/5)^3
y = 10×27/125
y = 54/25