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A cyclist speeding at 18km/h on a level road takes a sharp circular turn of radius 3m without reducing the speed.Tje co-efficent of static friction between the tyres and roads is 0.1.Will the cyclist slip while taking the turn?​

User GarryOne
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2 Answers

14 votes
14 votes

Answer:

debits on the bank statement

User Lanoxx
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16 votes
16 votes

Answer: In general, airplane tracks are flat, they do not have cant, consequently the friction force is what keeps the bicycle in the circle.

Let's use Newton's second law, let's set a reference frame with the horizontal x-axis and the vertical y-axis.

Y axis y

N- W = 0

N = W

X axis (radial)

fr = m a

the acceleration in the curve is centripetal

a =

the friction force has the expression

fr = μ N

we substitute

μ mg = m v²/r

v =

we calculate

v =

v = 1,715 m / s

to compare with the cyclist's speed let's reduce to the SI system

v₀ = 18 km / h (1000 m / 1 km) (1 h / 3600 s) = 5 m / s

We can see that the speed that the cyclist is carrying is greater than the speed that the curve can take, therefore the cyclist will SKID

Step-by-step explanation:

User Ammouna
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