Question

See image, I need both answers.

Answer 1

#20

General truth

Conjugate base of H_2SO_3 is HSO_3^-

• k_b=7.143×10^{-13}

On comparing

• a=7
• b=143
• c=6.5
• d=2

#23

We need PH

• 0.2mol/L=0.2M

`\\ \rm\rightarrowtail pH=-log[H_3O^+]`

`\\ \rm\rightarrowtail pH=-log0.2`

`\\ \rm\rightarrowtail pH==-log 2-log10^(-1)`

`\\ \rm\rightarrowtail pH=-0.3+1`

`\\ \rm\rightarrowtail pH=0.7`

Highly acidic