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2^12÷2^(k/2 )= 32 find k​

1 Answer

5 votes

Answer:

k = 14

Explanation:

Prime factorize 32

32 = 2 * 2 * 2 * 2 * 2 = 2⁵


\frac{2^(12)}{2^{(k)/(2)}}= 32\\\\\frac{2^(12)}{2^{(k)/(2)}}=2^(5)\\\\2^{12-(k)/(2)}=2^(5)

Both sides base are same.So, compare exponents


12-(k)/(2)=5\\

Subtract 12 from both side


-(k)/(2)=5-12\\\\-(k)/(2)=-7\\

Multiply both sides by (-2),


(-2)*(-(k)/(2))=-7*(-2)\\\\k = 14

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