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Anjali has two sons, one being exactly 2 years older than the other. At present, her age is equal to the sum of the squares of the ages of her sons. If 6 years hence her age will be eight times the present age of the elder son, find their present ages.​

User Zarwan
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1 Answer

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\bold{\huge{\underline{ Solution }}}

Given :-

  • Anjali has two sons
  • One son is exactly 2 years older than the other
  • At present, Anjali age is equal to the sum of the squares of the ages of her sons
  • 6 years later, Anjali age will be 8 times the present age of the elder son

To Find :-

  • We have to find the present ages of the Anjali and his sons

Let's Begin :-

Let the present age of the younger son be x

Elder son is exactly 2 years older than younger son

Therefore,

  • The age of elder son is x + 2

According to the question,

The age of Anjali is equal to the sum of the squares of the ages of her sons

That is


\sf{ = x^(2) + ( x + 2)^(2)}


\sf{ = x^(2) + x^(2) + 4 + 2x }


\sf{ = 2x^(2) + 4x + 4 }

Now,

We have to find the age of mother and her sons after 6 years

After 6 years

The age of the younger son


\sf{ = (x + 6)\: years }

Therefore ,

The age of elder son


\sf{ = (x + 2) + 6 }


\sf{ = x + 2 + 6 }


\sf{ = x + 8 \: years }

Here, It is given that,

  • After 6 years the age of Anjali will be 8 times his elder son's age

That is,


\sf{ = 2x^(2) + 4x + 4 + 6 = 8( x + 8)}


\sf{ = 2(x^(2) + 2x + 2 + 3) = 8(x + 2)}


\sf{ = x^(2) + 2x + 2 + 3 = 4(x + 2)}


\sf{ = x^(2) + 2x + 5 = 4x + 8}


\sf{ = x^(2) + 2x - 4x = 8 - 5}


\sf{ = x^(2) - 2x = 3 }


\sf{ = x^(2) - 2x - 3 = 0 }

By factorization method


\sf{ =(x + 1)( x -3 )}


\sf{ = ( x = -1 ) or ( x = 3 )}

  • Age of the person can never be negative

Thus, The present age of the younger son is 3 years

Therefore,

Age of the elder brother


\sf{ = 3 + 2}


\bold{ = 5 \: years}

Present age of Anjali


\sf{ = 2(3)^(2) + 4(3) + 4 }


\sf{ = 2(9) + 12 + 4 }


\sf{ = 18 + 16 }


\bold{ = 34\: years }

Hence, The present age of Anjali and his two sons is 34 years, 5 years and 3 years .

User Hrant
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