Answer:
(0, -2)
Explanation:
a point on the y-axis. that means x=0.
so, the distance of (5, -2) to (0, y) is the same as the distance from (-3, 2) to (0, y).
the distance between (5, -2) and (0, y) is based on Pythagoras (the differences in x and y directions are the sides of a right-angled triangle, and the distance is its Hypotenuse, its baseline) :
distance² = (5-0)² + (-2 - y)² = 25 + 4 + 4y + y² = 29+4y+y²
but it is also
distance² = (-3-0)² + (2 - y)² = 9 + 4 - 4y + y² = 13 - 4y + y²
so, we get
29 + 4y + y² = 13 - 4y + y²
29 + 4y = 13 - 4y
16 = -8y
y = -16/8 = -2
their, the point on the y-axis being equidistant to both points is (0, -2)