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Would √x+6 -4 = x be an extraneous solution? The x + 6 are under the radicands line.
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Would √x+6 -4 = x be an extraneous solution? The x + 6 are under the radicands line.

User FLC
by
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1 Answer

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√(x + 6 ) = x + 4

now square both side

User Maurits Moeys
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