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2 votes
If K = (AB)/(A+B) , then B = ?

(a) (A)/(1−A)
(b) (AK)/(A−K)
(c) (AK)/(K−A)
(d) (A+K)/(A)
(e) (A−K)/(AK)

1 Answer

3 votes

Lets do


\\ \sf\longmapsto K=(AB)/(A+B)


\\ \sf\longmapsto (1)/(K)=(A+B)/(AB)


\\ \sf\longmapsto (1)/(K)=(1)/(A)+(1)/(B)


\\ \sf\longmapsto (1)/(B)=(1)/(K)-(1)/(A)


\\ \sf\longmapsto (1)/(B)=(K-A)/(AK)


\\ \sf\longmapsto B=(AK)/(K-A)

User Lev Denisov
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