Question

Find the area of ABCD

Answer 1

Applying Heron's Formula

`s=(2.89+4.3+6.81)/(2)`

`s_1=7`

`A_1=√(7(7-2.89)(7-4.3)(7-6.81))`

`A_1=10.56`

Now,
`s_2=(6.81+8.59+7.58)/(2)`

`s_2=11.49`

`A_2=√(11.49(11.49-6.81)(11.49-8.59)(11.49-7.59))`

`A_2=24.69`

Total Area:

`10.56+24.69`

`=35.25`

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