Question

Find the area of quadrilateral ABCD

Answer 1

A ≈ 28.5

Explanation:

a, b, c

P = a + b + c

Semiperimeter s =
`(a+b+c)/(2)`

A =
`√(s(s-a)(s-b)(s-c))`

~~~~~~~~~~~~~~~

`P_(ABC)` = 4.3 + 2.89 + 6.81 = 14

s = 14 ÷ 2 = 7

`A_(ABC)` =
`√(7(7-4.3)(7-2.89)(7-6.81))` = √14.75901 ≈ 3.84

`P_(BCD)` = 8.59 + 7.58 + 6.81 = 22.98

s = 22.98 ÷ 2 = 11.49

`A_(BCD)` =
`√(11.49(11.49-8.59)(11.49-7.58)(11.49-6.81))` = √609.7343148 ≈ 24.6928

`A_(ABCD)` = 3.84 + 24.6928 ≈ 28.5