Question

17. Find an equation of the straight line that is perpendicular to x - y = 5 and passes through the point (8, -1).

18. Find the equation of the line in slope-intercept form that passes through the points (12, 4) and (4, 6)

Answer 1

17.y=-x+12

18.y=-1/4x+7

Explanation:

17.a Solve for y (y=-5+x)

17. b Reciprocal (y=-1x-5)

17. c Subsitute equation into (8,-1) (-1=-13=y=x+12)

18.a Subtract y values and x values= (6-4)/(4-12)=2/-8=-1/4, this will be your slope

18. b Plug in -1/4 into either of the two ordered pairs to find y value=(12,4)=(4=-3)=y value=7.

18. c=y=-1/4x+7