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There is a line that includes the point (1, 15)and has a slope of 0 .What is its equation in slope-intercept form?

User Jiyoon
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Answer:

Point on line (1,15)

It has slope of 0 .

here

x₁ = 1

y₁ = 15

m = 0

we are asked to find the equation in slope -intercept form .

Using Slope - Intercept form formula :


\bf \: y - y_(1) = m(x - x_(1))

Put the given value we obtain


\sf \dashrightarrow \: y - 15 = 0(x - 1) \\ \\ \sf \dashrightarrow \: y - 15 = 0 \\ \\

So, the equation of slope -intercept form is y-15 = 0.

User Ultrajohn
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