Question

. Two charges, Q1 and Q2 , are separated by a certain distance R. If the magnitudes of the charges are halved, and their separation is also halved, then what happens to the electrical force between these charges

Answer 1

Answer: Magnitude of electrical force stays the same.

Step-by-step explanation:

Equation:

`F_(e) =k(Q_(1)Qx_(2) )/(r^(2) )`

Since the magnitude of each charge is halved.

and

the separation is halved.

`F_(e) =k((.5Q_(1)*.5Q_(2) )/((.5r)^(2) )`

`F_(e) =k(.25*Q_(1)Qx_(2) )/(.25*r^(2) )`

Cancel out .25 on the numerator and denominator. Leaving the original equation.