Answer:
129 g of CuO
Step-by-step explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
CuCO₃ —> CuO + CO₂
Next, we shall determine the mass of CuCO₃ that decomposed and the mass of CuO produced from the balanced equation. This can be obtained as follow:
Molar mass of CuCO₃ = 64 + 12 + (16×3)
= 64 + 13 + 48
= 124 g/mol
Mass of CuCO₃ from the balanced equation = 1 × 124 = 124 g
Molar mass of CuO = 64 + 16
= 80 g/mol
Mass of CuO from the balanced equation = 1 × 80 = 80 g
SUMMARY:
From the balanced equation above,
124 g of CuCO₃ decomposed to produce 80 g of CuO.
Finally, we shall determine the mass of CuO produced by the decomposition of 200 g of CuCO₃. This can be obtained as follow:
From the balanced equation above,
124 g of CuCO₃ decomposed to produce 80 g of CuO.
Therefore, 200 g of CuCO₃ will decompose to produce
= (200 × 80)/124 = 129 g of CuO.
Thus, 129 g of CuO was obtained from the reaction.