Question

Simplify. can someone help i am lost

Answer 1

9514 1404 393

Answer:

`(S)\cdot(H)\cdot(E)\cdot(e)\cdot(\theta)\cdot(\epsilon+1+1)\cdot(\xi)\cdot(s)\cdot(h)`

Explanation:

The inverse function of fun(x) is indicated using a -1 exponent. That is ...

`\text{fun}(\text{fun}^(-1)(x)) = x\\\text{fun}^(-1)(\text{fun}(x)) = x`

The usual trig identities apply:

sin²(x) +cos²(x) = 1

sec²(x) -tan²(x) = 1

sin(x) = 1/csc(x)

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So, the expression simplifies to ...

`(S)\cdot(H)\cdot(E)\cdot(e)\cdot(\theta)\cdot(\epsilon+1+1)\cdot(\xi)\cdot(s)\cdot(h)`