Question

Please help its urgent:

A bag contains one tile for each letter of the word PANDA. If you selected a permutation of these letters at random, what is the probability that they would spell the word panda?

Answer 1

Using Permutation

`\boxed{\sf ^nP_r=n!}`

`\\ \sf\longmapsto ^5P_r=5!`

`\\ \sf\longmapsto 1* 2* 3* 4* 5`

`\\ \sf\longmapsto 120`

Now

`\\ \sf\longmapsto P(Panda)=(2)/(120)`

`\\ \sf\longmapsto P(Panda)=(1)/(60)`

Answer 2

• 1/60

Explanation:

Permutations of "Panda"

• 5P5 = 5! = 120

Two of the 'Panda" s we can get as a result

• P(Panda) = 2/120 = 1/60