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4 votes
Hello i need help someone please!!

find the inverse of this relation
h(t) = -6t + 7

User Toam
by
4.6k points

2 Answers

4 votes

Answer:


h^(-1) (t) =
(7-t)/(6)

Explanation:

let y = h(t) and rearrange making t the subject

y = - 6t + 7 ( add 6t to both sides )

6t + y = 7 ( subtract y from both sides )

6t = 7 - y ( divide both sides by 6 )

t =
(7-y)/(6)

Change y back into terms of x with t =
h^(-1) (t)


h^(-1) (t) =
(7-t)/(6)

User Nicktruesdale
by
4.3k points
5 votes

Answer:

73

Explanation:

User Adarsh Gowda K R
by
4.6k points