Answer:
1.D
2.B
Explanation:
1. The x intercept is the value of x when y is zero. We know that the x intercept is 0.5 so we must find a value of k that will make our rational function equal zero when x=0.5
![y = (k)/(x + 1) - 2](https://img.qammunity.org/2022/formulas/mathematics/college/d5vu3q2whxl9kied3lbj89ru5emngyscz0.png)
Substitute x=0.5 and y=0.
![0 = (k)/(0.5 + 1) - 2](https://img.qammunity.org/2022/formulas/mathematics/college/ipu59g8irsigzuuf0oundx7bj61q810t5c.png)
![0= (k)/(1.5) - 2](https://img.qammunity.org/2022/formulas/mathematics/college/p97qxp8m1i7n8n8qzeoeiqk6vy7xaubvp2.png)
![2 = (k)/(1.5)](https://img.qammunity.org/2022/formulas/mathematics/college/s6bs2emltzeao0rpdkqqhhhn4ryv1qgm20.png)
![3 = k](https://img.qammunity.org/2022/formulas/mathematics/high-school/nn3ypji5eb6hzdivtk5afbij7z1z72u34p.png)
D is the Answer.
2. We need to consider the function
![\frac{2x}{1 - {x}^(2) }](https://img.qammunity.org/2022/formulas/mathematics/college/eifthrn0mhn3p9il1hcxv2g8y23j56ch20.png)
Since the numerator is a linear term, it will have one zero to the equation using fundamental Theorem of Algebra so C is wrong.
This is a rational function because we are dividing two polynomials by each other and q(x) or the denominator isnt zero. So D is wrong.
The denominator is a quadratic term so it will have two vertical asymptote according to the fundamental Theorem of Algebra So A is Wrong.
B is Right, the equation isnt defined at x=0 because when we plug 0 into the denominator, it doesn't equate to zero.