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Help! Can somebody explain the answer and how they got it?

"Write the equation for the first ionization of potassium."

User Tim Siegel
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Answer:

K°(g)* + 419 Kj/mole => K⁺(g) + e⁻

Step-by-step explanation:

1st ionization step for potassium is the ionization of the 4s¹ electron. This requires 419 Kj/mole energy (endothermic). The reaction equation is ...

K°(g)* + 419 Kj/mole => K⁺(g) + e⁻

*note: Ionization of group IA metals requires they be in gas phase. That is, as shown by the Born-Haber Cycle** for formation of ionic compounds ...

K°(s) + 89.24 Kj/mole => K°(g); then ...

K°(g) + 419 Kj/mole => K⁺(g).

**Recommend review of Born-Haber cycle for formation of ionic compounds.

User Bil Simser
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