Answer:
The probability is: 0.8889.
Explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Approved
Event B: Qualified
Probability of a person being approved:
80% of 75%(qualified)
30% of 25%(not qualified). So
![P(A) = 0.8*0.75 + 0.3*0.25 = 0.675](https://img.qammunity.org/2022/formulas/mathematics/college/5vq9cxele4fw5r3f4pu4gdgul5fpf67g0b.png)
Probability of a person being approved and being qualified:
80% of 75%, so:
![P(A \cap B) = 0.8*0.75](https://img.qammunity.org/2022/formulas/mathematics/college/3m0k0yvr0xsriwcghqomq0ddit44cp7019.png)
Find the probability that a person is qualified if he or she was approved by the manager.
![P(B|A) = (P(A \cap B))/(P(A)) = (0.8*0.75)/(0.675) = 0.8889](https://img.qammunity.org/2022/formulas/mathematics/college/2tmualvj76l7i12z6b7vsytgn5bb6pw8zt.png)
The probability is: 0.8889.