Answer:
90
Explanation:
We know that area of ∆BCD = half of the area of rectangle BEFD, since any triangle drawn from taking a side and base and a point on the opposite side as the 3rd vertex has the half area of the rectangle
so, area of ∆BCD = 15×12/2 = 90 (since two legs of the right triangle are 15 and 12)
since area ∆BCD is half the area rectangle BEFD and sum of the area of ∆BEC and ∆CFD will be the rest of the area of rectangle BEFD, which is 90