Answer:
hello,
Explanation:
c(1)=5
c(2)=9
c(2)-c(1)=9-5=4
c(3)=13
c(3)-c(2)=13-9=4
c(4)=17
c(4)-c(3)=17-13=4
c(5)=21
c(5)-c(4)=21-17=4
for n=1,2,...,k :
c(n+1)-c(n)=4 and c(n+1)=4*(n+1)+1=4n+5
c(1)=1
T0 = a³+4
T1 = a⁴x a¹ +4
T2= a³ + a³ + 4
T3= a⁴ + a⁴* a² + 4
T4= a⁴ + a⁴ x a¹ + 4
T5= a³ + a³ + a⁴+4
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