Question

Find the Area of the figure below, composed of a rectangle with a semicircle removed from it. Round to the nearest tenth place.

4
8

Answer 1

In rectangle

Area:-

• Length ×Breadth
• 8(4)
• 32units^2

In semicircle

• Radius=4/2=2

Area:-

• πr^2/2
• 2π=6.28units^2

Total area=

• 32-6.28
• 25.72units^2

Answer 2

Explanation:

the rectangle's area is simply: A = 4 x 8 = 32

the circle's area is : π x 2 x 2 so A = 4π

the half circle's area is : 4π / 2 = 2π

And the final area is A = 32 - 2π = 2 x (16-π)