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Find the length of side x to the nearest tenth

Find the length of side x to the nearest tenth-example-1

2 Answers

2 votes

Answer:

9.9

Explanation:

Since this is a right and isosolese triangle, the adjacent side is also 7, so

c**2 = a**2 + b**2

c**2 = 7**2 + 7**2

c**2 = 49 + 49 = 98

c = +- (98)**1/2

c = 9.9

User Chanafot
by
5.5k points
5 votes

Answer:

9.9

Explanation:

x = √(7²+7²)

= √(49+49)

= √(49×2)

= 7√2

= 9.9 (rounded to the nearest tenth)

Answered by GAUTHMATH

User Ben Bartle
by
5.4k points