Question

You are to connect resistors R1 andR2, with R1 >R2, to a battery, first individually, then inseries, and then in parallel. Rank those arrangements according tothe amount of current through the battery, greatest first. (Useonly the symbols > or =, for exampleseries>R1=R2>parallel.)

Answer 1

The current is more in the parallel combination than in the series combination.

Step-by-step explanation:

two resistances, R1 and R2 are connected to a battery of voltage V.

When they are in series,

R = R1 + R2

In series combination, the current is same in both the resistors, and it is given by Ohm's law.

V = I (R1 + R2)

`I = (V)/(R_1 + R_2)`..... (1)

When they are connected in parallel.

the voltage is same in each resistor.

The effective resistance is R.

`R = (R_1R_2)/(R_1 + R_2)`

So, the current is

`I = (V(R_1+R_2))/(R_1 R_2)`..... (2)

So, the current is more is the parallel combination.