Question

Magnesium metal burns in presence of oxygen gas to produce magnesium oxide. What mass of magnesium oxide will be produced if 500.0 g of magnesium is available to react with 300.0 g of oxygen

Answer 1

Approx.

300

⋅

m

g

Step-by-step explanation:

We use the Ideal Gas Equation to access the molar quantity of dioxygen gas............

n

=

P

V

R

T

=

0.927

⋅

a

t

m

×

0.4981

⋅

L

0.0821

⋅

L

⋅

a

t

m

K

⋅

m

o

l

×

418.4

⋅

K

=

1.34

×

10

−

2

⋅

m

o

l

.

Given the stoichiometric equation..........

M

g

(

s

)

+

O

2

(

g

)

→

M

g

O

(

s

)

There are

1.34

×

10

−

2

⋅

m

o

l

×

24.31

⋅

g

⋅

m

o

l

−

1

=

?

?

⋅

g

metal required for stoichiometric equivalence.