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given a geomatric progression 2,6,18,54... find the smallest value of n such that the nth term is greater than 100000​
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given a geomatric progression 2,6,18,54... find the smallest value of n such that the nth term is greater than 100000​

User Calvin Ellington
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Answer:

hello,

Explanation:


u_1=2=2*3^0\\u_2=6=2*3^1\\u_3=18=2*3^2\\u_4=54=2*3^3\\\\....\\u_n=2*3^(n-1)\geq 100000\\\\3^(n-1)\geq 50000\\\\(n-1)*ln(3)\geq ln(50000)\\\\n-1\geq 9,848586...\\\\n\geq 10.848586....\\\\\boxed{n=11}\\

User Djq
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