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You're carrying a 3.0-m-long, 24 kg pole to a construction site when you decide to stop for a rest. You place one end of the pole on a fence post and hold the other end of the pole 35 cm from its tip. How much force must you exert to keep the pole motionless in a horizontal position?

1 Answer

1 vote

Answer:


F=133N

Step-by-step explanation:

From the question we are told that:

Length
l=3.0m

Mass
m=24kg

Distance from Tip
d=35cm

Generally, the equation for Torque Balance is mathematically given by


mg(l/2)=F(l-d)


2*9.81(3/2)=F(3-35*10^-2)

Therefore


F=133N

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