How do I solve part A

Question

asked Sep 7, 2022 38.9k views

1 Answer

Pookpash · Answer 1 · 2022-09-11T17:53:15+0000

Answer:

The solution of this expression is
x_(1) = -1 and
x_(2) = -(1)/(2) .

Explanation:

The procedure for solution of exercise A is described below:

1) We expand the expression.

2) The resulting expression is rearranged into the form of a second order polynomial.

3) Roots are found by Quadratic Formula.

Step 1:

$2\cdot x \cdot (x+1.5) = -1$

$2\cdot (x^(2)+1.5\cdot x) = -1$

$2\cdot x^(2) + 3\cdot x = -1$

Step 2:

$2\cdot x^(2)+3\cdot x +1 = 0$

Step 3:

$x_(1, 2) = \frac{-3\pm \sqrt{3^(2)-4\cdot (2)\cdot (1)}}{2\cdot (2)}$

$x_(1,2) = -(3)/(4)\pm (1)/(4)$

$x_(1,2) = (-3\pm 1)/(4)$

The solution of this expression is
x_(1) = -1 and
x_(2) = -(1)/(2) .