Question

How do I solve part A

Answer 1

The solution of this expression is
`x_(1) = -1` and
`x_(2) = -(1)/(2)`.

Explanation:

The procedure for solution of exercise A is described below:

1) We expand the expression.

2) The resulting expression is rearranged into the form of a second order polynomial.

3) Roots are found by Quadratic Formula.

Step 1:

`2\cdot x \cdot (x+1.5) = -1`

`2\cdot (x^(2)+1.5\cdot x) = -1`

`2\cdot x^(2) + 3\cdot x = -1`

Step 2:

`2\cdot x^(2)+3\cdot x +1 = 0`

Step 3:

`x_(1, 2) = \frac{-3\pm \sqrt{3^(2)-4\cdot (2)\cdot (1)}}{2\cdot (2)}`

`x_(1,2) = -(3)/(4)\pm (1)/(4)`

`x_(1,2) = (-3\pm 1)/(4)`

The solution of this expression is
`x_(1) = -1` and
`x_(2) = -(1)/(2)`.