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What is the decay constant for Oxygen-19 if it has a half-life of 26.5s?

A)0.0262/s

B)18.4

C)0.0377/s

C)38.2/s

User Tynn
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1 Answer

3 votes

Answer:

Option A.

Step-by-step explanation:

We define the half time T as the time such that an initial quantity A reduces to its half.

So we can model the quantity as a function of time like:

P(t) = A*e^(-k*t)

Then for the half time, T, we will have:

P(T) = A/2 = A*e^(-k*T)

solving for k, we get:

A/2 = A*e^(-k*T)

1/2 = e^(-k*T)

ln(1/2) = ln( e^(-k*T)) = -k*T

-ln(1/2)/T = k

Here we know that the half time is T = 26.5s

if we input that in the above equation, we get:

-ln(1/2)/26.5s = k = 0.0262 s^-1

Then the correct option is A

User CurtJRees
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