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What is the molarity of a solution made by mixing 75.0 mL of 3.00 M NH₄OH with enough water to give 250. mL of solution?

Please explain and show work.

2 Answers

4 votes
  • M1=3M
  • M2=?
  • V1=75mL
  • V2=250mL

We know


\boxed{\Large{\sf M_1V_1=M_2V_2}}


\\ \Large\sf\longmapsto M_2=(M_1V_1)/(V_2)


\\ \Large\sf\longmapsto M_2=(3(75))/(250)


\\ \Large\sf\longmapsto M_2=(225)/(250)


\\ \Large\sf\longmapsto M_2=0.9M

User Pberggreen
by
5.5k points
2 votes

Answer:

Mass 1=3M

Mass 2=?

Volume1=75mL

Volume2=250mL

By using molarity formula:

mass1*volume 1=mass2*volume 2

3M*75=mass2*250

mass2=225/250

mass2:0.9M

the molarity of a solution is 0.9M.

User Tguclu
by
6.0k points