Question

Three men and six women are waiting to be interviewed for jobs. If they are all selected in random order, find the probability that all men will be interviewed first.​

Answer 1

• 1/84

Explanation:

Total people:

• 3 + 6 = 9

Probabilities of men:

• P(first man) = 3/9 = 1/3
• P(second man) = 2/8 = 1/4
• P(third man) = 1/7

Required probability is:

• P(first 3 men) = 1/3*1/4*1/7 = 1/84