Question

Y= -(x+3)^2 -5
What is the leading coefficient?
How do you find the vertex?

Answer 1

To find the leading coefficient, first expand the function:

`y= -(x+3)^(2) -5\\\\y=-(x^(2) +6x+9)-5\\\\y=-x^(2) -6x-9-5\\\\y=-x^(2) -6x-14`

The leading coefficient is the coefficient of the highest-order term, which, in this case, would be the -1 from -x².

To find the vertex: see image below

Vertex = (-3, -5)