Question

A motorcyclist start from rest to reaches 6m/s with uniform acceleration for 3s what his acceleration?​

Answer 1

`\boxed {\boxed {\sf 2 \ m/s^2}}`

Step-by-step explanation:

Acceleration is the rate of change in velocity with respect to time. It is calculated by dividing the change in velocity by the change in time. The formula is:

`a= ( \Delta v)/(\Delta t)` or
`a= (v_f-v_i)/(\Delta t)`

The change in velocity is the difference between the initial velocity and the final velocity. The motorcycle starts at rest, or 0 meters per second and reaches 6 meters per second. The change in time is 3 seconds.

`\bullet \ v_f= 6 \ m/s\\\bullet \ v_i= 0 \ m/s \\\bullet \ \Delta t = 3 \ s`

Substitute the values into the formula

`a= \frac { 6 \ m/s - 0 m/s}{3 \ s}`

Solve the numerator.

`a= (6 \ m/s)/(3 \ s)`

`a= 2 \ m/s^2`

The motorcyclist's acceleration is 2 meters per second squared.