Question

What are the zeros of the polynomial function f(x)=x3-7x2+8x+16

Answer 1

Answer: x=4, -1

Step-by-step explanation:

Assuming you meant
`x^3-7x^2+8x+16`, the zeros of the question are x = 4 and -1.

Step 1. Replace f(x) with y.

`y = x^3-7x^2+8x+16`

Step 2. To find the roots of the equation, replace y with 0 and solve.

`0 = x^3-7x^2+8x+16`

Step 3. Factor the left side of the equation.

`(x-4)^2 (x+1)=0`

Step 4. Set x-4 equal to 0 and solve for x.

`x-4=0`

Step 5. Set
`x+1` equal to 0 and solve for x.

`x=-1`

The solution is the result of
`x-4=0` and
`x+1=0`.

`x=4,-1`