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A certain superconducting magnet in the form of a solenoid of length 0.28 m can generate a magnetic field of 7.0 T in its core when its coils carry a current of 80 A. The windings, made of a niobium-titanium alloy, must be cooled to 4.2 K. Find the number of turns in the solenoid.

User Genry
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Answer:

The number of turns in the solenoid is 19506.

Step-by-step explanation:

Length of solenoid, L = 0.28 m

Magnetic field, B = 7 T

Current, I = 80 A

Let the number of turns is N.

The formula used to find the magnetic field is


B = (\mu 0N I)/(L)\\\\7 = (4 * 3.14* 10^(-7)* N* 80)/(0.28)\\\\N = 19506

User Roboneter
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