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P(x) = x^4 – 2x^3 – 3x^2 + 4 What is the remainder when P(x) is divided by (x – 3)?​

P(x) = x^4 – 2x^3 – 3x^2 + 4 What is the remainder when P(x) is divided by (x – 3)?​
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P(x) = x^4 – 2x^3 – 3x^2 + 4

What is the remainder when P(x) is divided by (x – 3)?​

User Ricardo A
by
8.5k points

2 Answers

6 votes

Answer:

4

Explanation:

:)

User Jamey Graham
by
8.4k points
3 votes
Here is the answer using synthetic division method !
P(x) = x^4 – 2x^3 – 3x^2 + 4 What is the remainder when P(x) is divided by (x – 3)?​-example-1
User Stevejay
by
9.4k points
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