Question

Please help with all 3 parts!

Answer 1

It will help you !!!!!!!!!!

Answer 2

1:Part A.

`\bold{42.2 g C_(12)H_(22)O_(11) \:in \:528 g H₂O}`

Mass Percent=
`\bold{(Mass\: of \:Solute)/(Mass\: of \:Solution)×100\%}`

=
`(42.2)/(528)*100\%=\bold{\underline{7.99\: or \:8\%}}`

Part B.

`\bold{198\:m g\: C_(6)H_(12)O_(6) \:in\:4.71 g\: H₂O}`

mass of solute: 198mg

mass of solvent :4.71g=4710g

Mass Percent=
`\bold{(Mass\: of \:Solute)/(Mass\: of \:Solution)×100\%}`

=
`(198)/(4710)*100\%=\bold{\underline{4.20\%}}`

Part C.

`\bold{8.85 g NaCl \:in \:190 g\: H₂O}`

Mass Percent=
`\bold{(Mass\: of \:Solute)/(Mass\: of \:Solution)×100\%}`

=
`(8.85)/(190)*100\%=\bold{\underline{4.66\%}}`