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A particle is moving such that its height h at time t is given by h(t) = 2 + 8t - 3t^2 + 1/5t^3. The average velocity of the particle on the period [0,3] is

User Debran
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1 Answer

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  • t=3


\\ \Large\sf\longmapsto h(t)


\\ \Large\sf\longmapsto 2+8t-3t^2+(1)/(5)t^3


\\ \Large\sf\longmapsto 2+8(3)-3(3)^2+(1)/(5)(3)^3


\\ \Large\sf\longmapsto 2+24-3(9)+(27)/(5)


\\ \Large\sf\longmapsto 26-27+5.4


\\ \Large\sf\longmapsto -2+5.4


\\ \Large\sf\longmapsto h(t)=3.4m

User Bobbo
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