2 Answers

Shubho Shaha · Answer 1 · 2022-11-09T21:59:24+0000

$\:$

1 mole of KCl → 22.4l

1 mole of KCl → 74.55g

we have

0.14 mole of KCl → 74.55*0.14=10.347g

74.55g of KCl → 22.4l

10.347 g of KCl → 22.4/74.55*10.347=3.11litre

volume of each solution contains 0.14 mol of KCl contain 3.11litre.

Alireza Amrollahi · Answer 2 · 2022-11-13T22:00:14+0000

Answer:

Solution given:

1 mole of KCl
$\rightarrow$ 22.4l

1 mole of KCl
$\rightarrow$ 74.55g

we have

0.14 mole of KCl
$\rightarrow$ 74.55*0.14=10.347g

74.55g of KCl
$\rightarrow$ 22.4l

10.347 g of KCl
$\rightarrow$ 22.4/74.55*10.347=3.11litre

volume of each solution contains 0.14 mol of KCl contain 3.11litre.

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