Question

A wire, 0.60 m in length, is carrying a current of 2.0 A and is placed at a certain angle with respect to the magnetic field of strength 0.30 T. If the wire experiences a force of 0.18 N, what angle does the wire make with respect to the magnetic field

Answer 1

`\theta=30 \textdegree`

Step-by-step explanation:

From the question we are told that:

Current
`I=2.0A`

Length
`L=0.60m`

Magnetic field
`B=0.30T`

Force
`F=0.18N`

Generally the equation for Force is mathematically given by

`F = BIL sin\theta`

`sin\theta=(F)/(BIL)`

`\theta=sin^(-1)(0.18)/(0.3*2*0.6)`

`\theta=30 \textdegree`