Question

Propane gas reacts with oxygen according to this balanced equation: C subscript 3 H subscript 8 space (g )space plus space 5 space O subscript 2 space (g )space rightwards arrow 3 space C O subscript 2 space (g )space plus space 4 space H subscript 2 O space (g )How many liters of carbon dioxide are produced at STP when 44 g of C3H8 completely reacts with oxygen

Answer 1

Step-by-step explanation:

The balanced chemical equation of the reaction is:

`C_3H_8(g)+ 5O_2 (g)->3CO_2(g)+4H_2O(g)`

From the balanced chemical equation,

1 mole of propane forms ------ 3 mol. of
`CO_2` gas.

The molar mass of propane is 44.1 g/mol.

One mole of any gas at STP occupies --- 22.4 L.

Hence, 44 g of propane forms (3x22.4 L=) 67.2 L of CO2 gas at STP.

Answer:

Thus, 67.2 L of CO2 is formed at STP.