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Consider a piston filled with 3 mols of an ideal gas, kept at a constant temperature 290 K. We slowly compress the gas starting at 2 m3 and ending at 1 m3. How much work do we need to do on the gas to perform this operation

1 Answer

5 votes

Answer:
-5013.65\ J

Step-by-step explanation:

Given

No of moles
n=3

Temperature
T=290\ K

Initial volume
V_1=2\ m^3

Final volume
V_2=1\ m^3

Work done in constant temperature process is


W=nRT\ln \left((V_2)/(V_1)\right)

Insert the values


\Rightarrow W=3* 8.314* 290\ln \left ((1)/(2)\right)\\\\\Rightarrow W=-870* 8.314* \ln (2)\\\Rightarrow W=-5013.65\ J

User Dyin
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