Question

a recent survey shows that 66% of college students have a cat and 37% have a HBO subscription. Assuming these two events are independent, what is the probability that a randomly selected student has neither a cat nor HBO

Answer 1

`P(C'\ and\ H') =0. 2178`

Explanation:

Let

`C \to` Student with cat

`H \to` Student has HBO sub

`P(C) = 66\% \\ P(H) = 37\%`

Required

`P(C'\ and\ H')`

This is calculated as:

`P(C'\ and\ H') = P(C') * P(H')`

Using complement rules, we have:

`P(C'\ and\ H') = [1 - P(C)] * [1 - P(H)]`

So, we have:

`P(C'\ and\ H') = [1 - 66\%] * [1 - 37\%]`

`P(C'\ and\ H') = [33\%] * [66\%]`

`P(C'\ and\ H') =0. 2178`