Question

During normal beating, the heart creates a maximum 4.10-mV potential across 0.350 m of a person's chest, creating a 1.00-Hz electromagnetic wave. (a) What is the maximum electric field strength created? V/m (b) What is the corresponding maximum magnetic field strength in the electromagnetic wave? T (c) What is the wavelength of the electromagnetic wave?

Answer 1

Step-by-step explanation:

Given that,

Maximum potential, V = 4. mV

Distance, d = 0.350 m

Frequency of the wave, f = 100 Hz

(a) The maximum electric field strength created is given by:

`E=(V)/(d)\\\\E=(4.1* 10^(-3))/(0.350 )\\\\E=0.0117\ V/m`

(b) The corresponding maximum magnetic field strength in the electromagnetic wave is given by :

`B=(E)/(c)\\\\B=(0.0117)/(3* 10^8)\\\\B=3.9* 10^(-11)\ T`

(c) The wavelength of the electromagnetic wave can be calculated as :

`\lambda=(c)/(f)\\\\\lambda=(3* 10^8)/(100)\\\\=3* 10^6\ m`

So, the wavelength of the electromagnetic wave is
`3* 10^6\ m`.