Question

The sample concentration was measured at 50mg/ml. The loading concentration needs to be 10mg/ml. The final volume needs to be 25ul. What is the volume of sample needed and the amount of buffer needed to reach 25ul

Answer 1

a)
`V_1=5ul`

b)
`v=20ul`

Step-by-step explanation:

From the question we are told that:

initial Concentration
`C_1=50mg/ml`

Final Concentration
`C_2=10mg/ml`

Final volume needs
`V_2 =25ul`

Generally the equation for Volume is mathematically given by

`C_1V_1=C_2V_2`

`V_1=(C_1V_1)/(C_2)`

`V_1=(10*25)/(50)`

`V_1=5ul`

Therefore

The volume of buffer needed is

`v=V_2-V_1\\\\v=25-5`

`v=20ul`